How many grams of potassium phosphate must be dissolved in 3.75 Liters of water to produce a soltuion that contains 8*10^23 potassium ions?
Answered above.
To find out how many grams of potassium phosphate must be dissolved in 3.75 liters of water to produce a solution with 8*10^23 potassium ions, we need to follow a series of steps:
Step 1: Determine the molar mass of potassium phosphate.
- The chemical formula for potassium phosphate is K3PO4.
- The molar mass of potassium (K) is 39.10 g/mol.
- The molar mass of phosphorus (P) is 30.97 g/mol.
- The molar mass of oxygen (O) is 16.00 g/mol.
- The molar mass of potassium phosphate (K3PO4) is (39.10 g/mol * 3) + 30.97 g/mol + (16.00 g/mol * 4).
Step 2: Convert the given liters of water to milliliters.
- 1 liter is equal to 1000 milliliters.
- So, 3.75 liters is equal to 3.75 * 1000 = 3750 milliliters.
Step 3: Calculate the number of moles of potassium ions.
- Avogadro's number tells us that 1 mole of any substance contains 6.022 * 10^23 particles.
- In this case, we have 8 * 10^23 potassium ions, which is greater than Avogadro's number, indicating that we have more than 1 mole.
- We can find the number of moles by dividing the number of ions by Avogadro's number.
- So, the number of moles of potassium ions is (8 * 10^23) / (6.022 * 10^23).
Step 4: Use the stoichiometry of the balanced chemical equation to determine the moles of potassium phosphate.
- The balanced chemical equation for the dissociation of potassium phosphate is: 3K3PO4 → 9K+ + 3PO4^3-.
- From the balanced chemical equation, we can see that for every 3 moles of potassium phosphate, we get 9 moles of potassium ions.
- Therefore, we need to divide the number of moles of potassium ions by 9.
Step 5: Calculate the mass of potassium phosphate using its molar mass.
- Multiply the number of moles of potassium phosphate by its molar mass.
By following these steps, you can find the number of grams of potassium phosphate required to produce the desired solution.