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October 1, 2014

October 1, 2014

Posted by **carolyn** on Sunday, February 12, 2012 at 4:51pm.

- algebra -
**Damon**, Sunday, February 12, 2012 at 5:26pmin flow rate Q1 = 1 tank / 30 seconds

out flow rate = Q2

Q2 - Q1 = 1 tank/6 seconds

Q2 - 1/30 = 1/6

Q2 = 5/30 + 1/30 = 6/30 = 1/5 = 1 tank/5 seconds

so

5 seconds

- algebra -
**Reiny**, Sunday, February 12, 2012 at 5:35pmlet the tank hold 1 unit of volume

let the rate of water flowing in be y units/sec

let the water flowing out be x units / sec

When drain is open (water going in and out at the same time)

6(x-y) = 1

x - y = 1/6

drain closed: 30y = 1

y = 1/30

plug back into x-y = 1/6

x - (1/30) = 1/6

x = 1/5

only drain open:

t(1/5) = 1

t = 5 sec

With the drain only,

it would take 5 seconds to empty the tank

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