in flow rate Q1 = 1 tank / 30 seconds
out flow rate = Q2
Q2 - Q1 = 1 tank/6 seconds
Q2 - 1/30 = 1/6
Q2 = 5/30 + 1/30 = 6/30 = 1/5 = 1 tank/5 seconds
let the tank hold 1 unit of volume
let the rate of water flowing in be y units/sec
let the water flowing out be x units / sec
When drain is open (water going in and out at the same time)
6(x-y) = 1
x - y = 1/6
drain closed: 30y = 1
y = 1/30
plug back into x-y = 1/6
x - (1/30) = 1/6
x = 1/5
only drain open:
t(1/5) = 1
t = 5 sec
With the drain only,
it would take 5 seconds to empty the tank
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