solve the equation 4^2x-2b= (1/8)^x+b for x in terms of b.
I will assume that you meant to say ....
4^(2x-2b) = (1/8)^(x+b)
The way you typed it, solving for b would be a total nightmare.
2^(4x - 4b) = 2^(-3x - 3b)
4x - 4b = -3x - 3b
7x = b
x = b/7
(remember 4= 2^2 , and 1/8 = 1/2^3= 2^-3 )
Thank you so much Reiny =]