Posted by Willis on Saturday, February 11, 2012 at 8:04pm.
solve the equation 4^2x2b= (1/8)^x+b for x in terms of b.
1) x=b/7
2) x=7b
3) x=7b
4)x= b/7

Math  Reiny, Saturday, February 11, 2012 at 8:28pm
I will assume that you meant to say ....
4^(2x2b) = (1/8)^(x+b)
The way you typed it, solving for b would be a total nightmare.
2^(4x  4b) = 2^(3x  3b)
4x  4b = 3x  3b
7x = b
x = b/7
(remember 4= 2^2 , and 1/8 = 1/2^3= 2^3 )

Math  william, Saturday, February 11, 2012 at 8:38pm
Thank you so much Reiny =]
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