Posted by **Willis** on Saturday, February 11, 2012 at 8:04pm.

solve the equation 4^2x-2b= (1/8)^x+b for x in terms of b.

1) x=b/7

2) x=7b

3) x=-7b

4)x= -b/7

- Math -
**Reiny**, Saturday, February 11, 2012 at 8:28pm
I will assume that you meant to say ....

4^(2x-2b) = (1/8)^(x+b)

The way you typed it, solving for b would be a total nightmare.

2^(4x - 4b) = 2^(-3x - 3b)

4x - 4b = -3x - 3b

7x = b

x = b/7

(remember 4= 2^2 , and 1/8 = 1/2^3= 2^-3 )

- Math -
**william**, Saturday, February 11, 2012 at 8:38pm
Thank you so much Reiny =]

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