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calculus

posted by on .

Let f(x) be the function 1/x+5. Then the quotient
f(6+h)−f(6)/h can be simplified to −1/ah+b for:

a= 11

b=

I did all the work to get a but for some reason the number that I keep getting for "B" is wrong

  • calculus - ,

    prove d/dx (csc x) = −csc x cot x

  • calculus - ,

    First of all , I think you meant f(x) = 1/(x+5)

    the difference quotient is
    (f(l+h) - f(6))/h
    = (1/(11+h) - 1/11 )/h
    = (11 - 11 - h)/(11(11+h) (1/h)
    = -1 / (11(11+h))

    I notice another error is your typing
    you probably meant to type:
    ..... can be simplified to -1/(a(h+b) )

    compare -1/(11(11+h)) to -1/(a(h+b))
    since we are told a=11, clearly b has to be 11 for them to match

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