Posted by **cassie** on Friday, February 10, 2012 at 1:22am.

Let f(x) be the function 1/x+5. Then the quotient

f(6+h)−f(6)/h can be simplified to −1/ah+b for:

a= 11

b=

I did all the work to get a but for some reason the number that I keep getting for "B" is wrong

- calculus -
**hasan**, Friday, February 10, 2012 at 2:14am
prove d/dx (csc x) = −csc x cot x

- calculus -
**Reiny**, Friday, February 10, 2012 at 8:30am
First of all , I think you meant f(x) = 1/(x+5)

the difference quotient is

(f(l+h) - f(6))/h

= (1/(11+h) - 1/11 )/h

= (11 - 11 - h)/(11(11+h) (1/h)

= -1 / (11(11+h))

I notice another error is your typing

you probably meant to type:

..... can be simplified to -1/(a(h+b) )

compare -1/(11(11+h)) to -1/(a(h+b))

since we are told a=11, clearly **b has to be 11** for them to match

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