An electron is a subatomic particle (m = 9.11 10-31 kg) that is subject to electric forces. An electron moving in the +x direction accelerates from an initial velocity of +5.21 105 m/s to a final velocity of +2.29 106 m/s while traveling a distance of 0.034 m. The electron's acceleration is due to two electric forces parallel to the x axis: 1 = +7.03 10-17 N, and 2, which points in the -x direction. Find the magnitudes of the net force acting on the electron and the electric force 2.

To find the magnitudes of the net force acting on the electron and the electric force 2, we can apply Newton's second law of motion:

net force = mass × acceleration

First, we need to find the acceleration of the electron. We can use the equation of motion:

final velocity^2 = initial velocity^2 + 2 × acceleration × distance

Plugging in the values:
(2.29 × 10^6 m/s)^2 = (5.21 × 10^5 m/s)^2 + 2 × acceleration × 0.034 m

Simplifying the equation:
5.2441 × 10^12 m^2/s^2 = 2.71041 × 10^11 m^2/s^2 + 0.068a

Rearranging the equation to solve for acceleration:
0.068a = 4.97359 × 10^12 m^2/s^2
a = (4.97359 × 10^12 m^2/s^2) / 0.068 m
a ≈ 7.306 × 10^13 m/s^2

Now that we have the acceleration, we can find the net force acting on the electron:

net force = mass × acceleration
net force = (9.11 × 10^-31 kg) × (7.306 × 10^13 m/s^2)
net force ≈ 6.648 × 10^-17 N

Next, let's find the electric force 2. We know that the net force is the vector sum of the two electric forces, so:

net force = force 1 + force 2

Rearranging the equation to solve for force 2:
force 2 = net force - force 1
force 2 = (6.648 × 10^-17 N) - (7.03 × 10^-17 N)
force 2 ≈ -3.82 × 10^-18 N

Therefore, the magnitudes of the net force acting on the electron and the electric force 2 are approximately 6.648 × 10^-17 N and 3.82 × 10^-18 N, respectively.