Post a New Question


posted by .

A hydraulic jack is designed so that when the handle is pushed down 1 m, the piston raising the load moves up 0.015 m.
IMA= 66.67
AMA= 26.67
Efficiency= 40%

At this efficiency, what is the force required to lift a 5000 N weight?

  • Physics -

    The ideal mechanical advantage is
    1/0.015 = 66.67 They tell you that already.

    Because of inefficiency (friction), you have to apply
    1/26.67 times the lifted weight, or 187.5 N

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question