How much heat (in ) is required to warm 11.0 of ice, initially at -13.0, to steam at 111.0? The heat capacity of ice is 2.09 and that of steam is 2.01

To calculate the amount of heat required to warm the ice from -13.0 °C to steam at 111.0 °C, we need to consider the following steps:

Step 1: Calculate the heat required to warm the ice to its melting point
The heat required to warm the ice from -13.0 °C to its melting point at 0 °C can be calculated using the formula:
Q1 = mass × specific heat capacity × temperature change

Given:
mass (m) = 11.0 g
specific heat capacity (C) = 2.09 J/g°C
initial temperature (T_initial) = -13.0 °C
final temperature (T_final) = 0 °C

Substituting the given values into the formula, we can calculate the heat (Q1):
Q1 = 11.0 g × 2.09 J/g°C × (0 °C - (-13.0 °C))

Step 2: Calculate the heat required to melt the ice
The heat required to convert the ice at its melting point (0 °C) to water can be calculated using the formula:
Q2 = mass × heat of fusion

Given:
mass (m) = 11.0 g
heat of fusion (ΔH_fusion) = 334 J/g

Substituting the given values into the formula, we can calculate the heat (Q2):
Q2 = 11.0 g × 334 J/g

Step 3: Calculate the heat required to warm the water from its melting point to the boiling point
The heat required to warm the water from 0 °C to its boiling point at 100 °C can be calculated using the formula:
Q3 = mass × specific heat capacity × temperature change

Given:
mass (m) = 11.0 g
specific heat capacity (C) = 4.18 J/g°C
initial temperature (T_initial) = 0 °C
final temperature (T_final) = 100 °C

Substituting the given values into the formula, we can calculate the heat (Q3):
Q3 = 11.0 g × 4.18 J/g°C × (100 °C - 0 °C)

Step 4: Calculate the heat required to vaporize the water into steam
The heat required to convert the water at its boiling point (100 °C) to steam can be calculated using the formula:
Q4 = mass × heat of vaporization

Given:
mass (m) = 11.0 g
heat of vaporization (ΔH_vaporization) = 2260 J/g

Substituting the given values into the formula, we can calculate the heat (Q4):
Q4 = 11.0 g × 2260 J/g

Step 5: Sum up the heats from all steps
To find the total heat required, we can sum up the heat values from all the steps:
Total heat = Q1 + Q2 + Q3 + Q4

Once you have calculated the individual heats for each step and summed them up, you will have the answer to the original question, i.e., the amount of heat required to warm 11.0 g of ice, initially at -13.0 °C, to steam at 111.0 °C.