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April 18, 2014

April 18, 2014

Posted by **Matt** on Tuesday, January 31, 2012 at 2:28am.

- Trig -
**MathGuru**, Tuesday, January 31, 2012 at 8:45pmAnswered in another post.

- Trig -
**Bosnian**, Thursday, February 2, 2012 at 2:00amtan ( x ) = sin ( x ) / cos ( x )

tan ( x ) + sin ( x ) =

sin ( x ) / cos ( x ) + sin ( x ) =

sin ( x ) * [ 1 / cos ( x ) + 1 ] =

sin ( x ) * [ sec ( x ) + 1 ] =

sin ( x ) * [ 1 + sec ( x )]

[ 1 + sec ( x ) ] / [ tan ( x ) + sin ( x ) ] =

[ 1 + sec ( x ) ] / [ sin ( x ) * [ 1 + sec ( x ) ] ] =

1 / sin ( x ) = cosec ( x )

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