A ball is tossed so that it bounces off the ground, rises to a height of 0.90 m, and then hits the ground again 0.50 m away from the first bounce.
How long is the ball in the air between the two bounces?
What is the ball's velocity in the x-direction?
What is the ball's speed just before the second bounce?
What is the angle of the velocity vector with respect to the ground right after the first bounce?
physics - Steve, Tuesday, January 17, 2012 at 3:07pm
s = 1/2 at^2
time to rise .9m:
.9 = 1/2 (9.8) t^2
t = .428 sec
.5m/.428s = 1.17m/s
v = at = 9.8*.428 = 4.19m/s
h = -14.4x^2 + 7.2x
h' = -28.8x + 7.2
h'(0) = 7.2
arctan(7.2) = 82 degrees
physics - dem, Tuesday, January 17, 2012 at 3:16pm
what is acceleration ?
internatìonal school of lusaka - dem, Tuesday, January 17, 2012 at 3:23pm
what is distance?