intermediate algebra
posted by cecelia on .
0.3x + 0.2y=5, 0.5x + 0.4y=11 using the substitution method

.3x + .2y = 5
so
3x + 2y = 50
y = 25  3x/2
.5x + .4y = 11
5x + 4y = 110
5x + 4(25  3x/2) = 110
5x + 100  6x = 110
x = 10
x = 10
y = 40