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You have a compound that is subject to decay. If you originally started with 80 g of the compound and you ended up with 5 grams 30 days later, what is the half-life of the compound?

  • chemistry - ,

    I would do it this way.
    ln(No/N) = kt
    ln(80/5) = k*30
    Solve for k, then
    k = 0.693/t1/2

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