Homework Help: calculus

Posted by Daniel on Monday, November 21, 2011 at 11:48pm.

Sketch the curve

y = x^3 - 12x^2 + 36x

I already did the question properly it is concave down at (0,4) and concave up at (4,infinity)

I found the abs max to be (2,32) and abs min to be (6,0)

What I wanted to know is when labeling the graph should I label the max/min as abs/local max or just abs max? I am having trouble figuring out if it is just an abs or a local.

calculus - Bosnian, Tuesday, November 22, 2011 at 1:58am
Go on: wolframalpha dot com

When page be open in rectangle type:

x^3 - 12x^2 + 36x

and click option =

After few seconds you will see everything about that function.

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