Posted by Daniel on .
Sketch the curve
y = x^3  12x^2 + 36x
I already did the question properly it is concave down at (0,4) and concave up at (4,infinity)
I found the abs max to be (2,32) and abs min to be (6,0)
What I wanted to know is when labeling the graph should I label the max/min as abs/local max or just abs max? I am having trouble figuring out if it is just an abs or a local.

calculus 
Bosnian,
Go on: wolframalpha dot com
When page be open in rectangle type:
x^3  12x^2 + 36x
and click option =
After few seconds you will see everything about that function.