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Consider the following reaction.
CH4(g) + 2 O2(g) CO2(g) + 2 H2O(l) ÄH = -891 kJ

Calculate the enthalpy change for each of the following cases.

1.00 103 L methane gas at 719 torr and 26°C is burned in excess oxygen.

  • Chemistry - ,

    I would use PV = nRT and solve for n = moles CH4. Then
    891 kJ/mol x n moles = heat released.

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