Posted by **HM** on Wednesday, November 9, 2011 at 3:39am.

A batch consists of 12 defective coils and 88 good ones. find the probability of getting two good coils when two coils are randomly selected if the first selection is replaced before the second is made.

Help me..

since it would be replaced would the answer be 0.7744 ?

- PROBABILITY MATH -
**drwls**, Wednesday, November 9, 2011 at 3:48am
No. (76/88)^2 = 0.7459

- PROBABILITY MATH -
**HM**, Wednesday, November 9, 2011 at 3:59am
how is it going to be 76/88 ?

- PROBABILITY MATH -
**drwls**, Wednesday, November 9, 2011 at 7:17am
It isn't. For two draws, it is the square of that.

There are 76 good coils out of 88. What does that tell you about the probabiloity of selecting a good one at random each time?

- PROBABILITY MATH -
**HM**, Wednesday, November 9, 2011 at 9:03am
My answer was correct.. Your answer is not in the choices :S

- PROBABILITY MATH -
**Reiny**, Wednesday, November 9, 2011 at 9:37am
There are a total of 100 coils, of which 88 are good

prob of getting 2 good ones in a row, after replacing the first

= (88/100)(88/100)

= (88/100)^2

= .7744

- PROBABILITY MATH -
**HM**, Wednesday, November 9, 2011 at 1:20pm
Thank you Reiny, that is what I thought.

Drwls I appreciate your effort anyway :)

- PROBABILITY MATH -
**nagwa**, Saturday, March 16, 2013 at 7:09pm
a batch consists of 12 defective clocks and 88 good ones find the probability of getting two good clocks when the two are randomly selected if the first selection is replaced before the second selection is made.

B- the first selection is not replaced.

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