Posted by Caroline on Wednesday, October 26, 2011 at 9:41pm.
draw the triangle.
Notice the base is horizontal frm -1,0 to 1,0
write the equation for the two legs
left leg: y=mx+b where m= (4/1)=4
y=4x+b
4=4*0+b or b=4
integrating the left side..
mass=INT y*(5+x)dx fro x=-1 to 0 do that inegral. Now on the right side, the leg equation is y=-4x+4
same equation as above, integrate from x=0 to 1
be certain in each area to use as y either (-4x+4) or y=(4x+4)
add the two masses
What I did was:
INT (-1,0) (4x+4)(5+x) dx
INT 4x^+36x+20
I integrated and got (4/3)x^3+18x^2+20x
and evaluated from -1 to 0 and got 10/3 g and then from 0 to 1 and got 118/3 grams added and got 128/3 g and that's not the answer. What am I doing wrong?
(4x+4)(5+x) = 4x^2 + 24x + 20
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