Question

y+2=10-y, (with a radical root sign over the y+2)

Answer 1

sqrt(y+2) = 10 - y,

Square both sids:
y+2 = 100 -20y + y^2,
y^2 - 20y - y = 2 -100,
y^2 - 21y = -98,
y^2 - 21y + 98 = 0,
(y-14)(y-7) = 0,

y-14 = 0,
Y = 14.

y-7 = 0,
Y = 7.

Solution Set: Y = 7, and 14.