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November 20, 2014

November 20, 2014

Posted by **Angel** on Thursday, September 22, 2011 at 9:18am.

D(t)=-10.61t^(3)+208.808t^(2)-168.202t+9775.234 donors, where t is the number of years after 1975. Find the inflection point(s) from t=0 through t=17 , if any exist.

a. There are no inflection points from t=0 through t=17 .

b. There is one inflection point at t=6.56.

c. There are inflection points at t=0 and t=17.

d. There is one inflection point at t=0.15.

e. There are inflection points at t=0, t=0.15,and t=17.

I thought it was B.

- Calculus -
**Bosnian**, Thursday, September 22, 2011 at 9:50amAn inflection point is a point on a curve at which the second derivative changes sign. You must find point where second derivative = 0

Go on:

wolframalpha dot com

When page be open in rectangle type:

second derivative of -10.61t^(3)+208.808t^(2)-168.202t+9775.234

and click option =

When you see result click option:

Show steps

Then in rectangle type:

solve 417.616-63.66t=0

Inflection point is:

t=6.5601

- Calculus -
**Angel**, Thursday, September 22, 2011 at 9:58amThanks, i thought it was B. your awesome.

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