maths
posted by pavatharani on .
if x=1/(23^1/2)
prove that
x^32x^27x+5=3

start with the equation:
x^3  2x^2  7x + 2 = 0
after two tries, I found x = 2 to be a solution
so it factors to
(x+2)(x^24x+1) = 0
from the second ...
x = (4 ± √12)/2 = 2 ± √3
but you told me x = 1/(2√3)
rationalizing this ...
1/(2√3) * (2+√3)/(2+√3)
= (2+√3)/(4  3) = 2 + √3
which is one of the values for x I got by solving the equation.