Posted by **Phillip** on Friday, July 29, 2011 at 1:41pm.

In thea diagram,ABCD is a trapezium with AB,DC and vertices A(-4;1),B(x;-3),C(1;y) and D.Determine the value of x if the distance AB is 5 units.

- geometry -
**Henry**, Friday, July 29, 2011 at 8:26pm
A(-4,1), B(x,-3).

(AB)^2 = (x-(-4))^2 + (-3-1)^2 = 5^2,

(x+4)^2 + 16 = 25 - 16 = 9 ,

Take sqrt of both sides:

x+4 = +- 3,

x = -4 +-3,

x = -1, and x = -7.

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