Posted by **Brittany** on Saturday, July 16, 2011 at 3:31am.

Consider the function f(x)=sqrt(2–5x^2), –5≤x≤1. The absolute minimum value is ____ and this occurs at x equals ______?

Found the max value to be 2 at x=0.

- CALCULUS -
**Reiny**, Saturday, July 16, 2011 at 8:12am
f'(x) = (1/2)(2 - 5x^2)^(-1/2) )(-10x)

= -5x(2-5x^2)^(-1/2)

= 0 for a max/min

This has only one solution, when x = 0

so the min occurs when x = 0 and

f(0) = √(2-0) = √2

- CALCULUS -
**jamie**, Saturday, September 17, 2011 at 11:43pm
4x2+24x+16y2-32y-12=0 need to know how to write in the standard form for ellipse it is a precalculus

## Answer This Question

## Related Questions

- calculus - Consider the function f(x)=(x^3)(e^9x), -2 is less than or equal to x...
- Calculus - If m ≤ f(x) ≤ M for a ≤ x ≤ b, where m is the...
- Calculus - If m ≤ f(x) ≤ M for a ≤ x ≤ b, where m is ...
- New Age Math - Suppose that y≤5x,3x≤y and 14x+15y≤1 together ...
- CALCULUS - Consider the function f(x)=5â€“4x^2 , -3â‰¤xâ‰¤1 The absolute maximum...
- Calculus - 1.Determine the maximum value of the function f(x)= 5^x -x^5 on the ...
- Calculus - 2. Determine the minimum value of the function f(x)= e^(-x) - 2e^x on...
- Math - Suppose that y≤5x,3x≤y and 14x+15...
- Math - Minimize C=7x+3y+4z 0≤x 0≤y 0≤z 100≤2x+3y+3z 120...
- Math - Minimize C=7x+3y+4z 0≤x 0≤y 0≤z 100≤2x+3y+3z 120...

More Related Questions