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March 6, 2015

March 6, 2015

Posted by **Anonymous** on Tuesday, June 14, 2011 at 2:52pm.

- algebra -
**Henry**, Tuesday, June 14, 2011 at 4:30pmh(x) = -16t^2 + 96t.

The parabola opens downward. Therefore,

the max. point is the vertex.

t(V) = -b/2a = -96 / -32 = 3s = The value of t at the vertex.

h=-16*3^2 + 96*3 = -144 + 288 = 144Ft

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