Posted by Liz on Tuesday, June 14, 2011 at 2:14pm.
so
[integral] 1/x dx form 1 to k = [integral] 1/x dx from k to 3
lnx from 1 to k = lnx from k to 3
ln k - ln1 = ln3 - lnk
2lnk = ln3 + ln1
ln (k^2) = ln3 + 0
k^2 = 3
k = √3
Thank you!!
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