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November 27, 2014

November 27, 2014

Posted by **Liz** on Tuesday, June 14, 2011 at 2:14pm.

- Calculus -
**Reiny**, Tuesday, June 14, 2011 at 2:27pmso

[integral] 1/x dx form 1 to k = [integral] 1/x dx from k to 3

lnx from 1 to k = lnx from k to 3

ln k - ln1 = ln3 - lnk

2lnk = ln3 + ln1

ln (k^2) = ln3 + 0

k^2 = 3

k = √3

- Calculus -
**Liz**, Tuesday, June 14, 2011 at 2:31pmThank you!!

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