Posted by **deepak** on Tuesday, May 24, 2011 at 5:01am.

find the maximum value of √3 cosθ-sinθ.???

- mathematics -
**drwls**, Tuesday, May 24, 2011 at 5:37am
You get a maximum when the derivative is zero.

-3 sin -cos = 0

tan = -1/3

= -30 degrees

3 cos-sin = 3/2 + 1/2 = 2

check: If theta = -29 degrees,

3 cos-sin = 1.5149 + 0.4848 = 1.9997

If theta = -31 degrees,

3 cos-sin = 1.4847 + 0.5150 = 1.9997

So it looks like the maximum is 2.

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