Monday

September 1, 2014

September 1, 2014

Posted by **Matt** on Wednesday, May 18, 2011 at 11:53pm.

T(x,t) = 38 + 3 sin[2£k(0.0290t ¡V5.00x) + 1.5pie]

What is the value of T(x,t) when t = 220.0 s, and x = 0.25m?

I first worked out the wavelength = 0.2m and then the period = 34.5 seconds then i rewrote the equation to be T(x,t) = 38+3cos[2n(0.029*220/34.5 - 5*0.25/0.2) + 1.5pie] which gave me 35.5 which is not the correct answer of 35.9. What have i done wrong?

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