Posted by Justin on Tuesday, May 10, 2011 at 3:18pm.
The driveshaft of a buildingâ€™s airhandling fan is turned at 300 RPM by a belt running on a 0.3mdiameter pulley. The net force applied by the belt on the pulley is 2000 N. determine the torque applied by the belt on the pulley, in N.m, and the power transmitted, in kW.

Thermo engineering  bobpursley, Tuesday, May 10, 2011 at 4:00pm
torque= force*radius
power= torque*angular speed where
angular speed= 300*2PI/60 rad/sec
this will give you power in watts.

Thermo engineering  jackson, Wednesday, September 10, 2014 at 1:05pm
torque=300Nm
power=31.41 Watts

Thermo engineering  Maddy, Friday, October 16, 2015 at 10:48pm
torque=F*D/2=2000n(0.15m)=300 N*m
Power = Torque*angular speed
=(300 N*m)(300 RPM) (2*PI/60)
=9424 W = 9.42 kW
These are the answers in the back of the text.
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