Posted by **Anonymous** on Wednesday, May 4, 2011 at 7:47am.

Cities A, B, C and D are equidistant. That is, B is d miles from A, C is d miles from B, and D is d miles from C. Suppose you travel 55 mph from A to B, 40 mph from B to C, and 50 Mph from C to D. What single, constant speed could you have traveled from A to B to C to D that would have taken the same amount of time?

I know that I am supposed to use harmonic mean. Just not sure how to set up formula.

## Answer this Question

## Related Questions

- Statstics - Cities A, B, C and D are equidistant. That is, B is d miles from A, ...
- Science - A car traveled at an average speed of 60 mph for two hours. How far ...
- math - 13. If two planes leave the same airport at 1:00 PM, how many miles apart...
- Math - A surfer drives his dune buggy out into the sand dunes.He follows his ...
- Trigonometry - An airplane is flying on a heading of 115° with a constant ...
- Calculus, antiderivatives - A student accelerates from rest at a rate of 3 miles...
- Math - Please help me? A motorist takes a trip of 100 miles, traveling at 40 mph...
- Math - Can someone please help me? I can't figure out the answer. A motorist ...
- Math - A boat travels 74 miles on a course with direction 34 degrees and then ...
- math - the group covered the first 70 miles in 10 hours. then it doubled its ...