Tuesday

September 30, 2014

September 30, 2014

Posted by **Jordan** on Monday, May 2, 2011 at 9:56pm.

What is the area of the region enclosed by the graphs of f(x) = x - 2x^2 and g(x)= -5x?

what is an easy way to tell if a function is above or under the other, so I can tell which function to put first in the integral. MUCH APPRECIATED!

- calculus -
**Reiny**, Monday, May 2, 2011 at 10:22pmI hope you found that the two functions intersect at

x = 0 and x = 3

so pick any value of x in that domain,

say x = 1

f(1) = 1 - 2 = -1

g(1) = -5

since f(x) is above g(x) for that value,

f(x) will be above g(x) for all values between 0 and 3

If you had two functions that would intersect at more than 2 values of x, you would have to test this for each of the regions.

**Answer this Question**

**Related Questions**

Calculus - Let f(x)=x^3+3x and g(x=5x^2-x Determine the area of the region ...

calculus - Consider the graphs of y = 3x + c and y^2 = 6x, where c is a real ...

calculus - 1. Let R be the region in the first quadrant enclosed by the graphs ...

Calculus - please help! - Suppose that 0 < c < ¥ð/2. For what value of c ...

Calculus - 4. Find the area of the largest rectangle (with sides parallel to the...

Calculus 1 - Let f be the function given by f(x)=3sqrt(x-2). A) On the axes ...

calculus - Find the area and dimensions of the largest rectangle (with sides ...

Calculus - MathMate Please help - I asked this question on last thursday and u ...

Calculus Help!!! - Find c > 0 such that the area of the region enclosed by ...

calculus - Let A be the bounded region enclosed by the graphs of f(x) = x , g(x...