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March 3, 2015

Posted by **H.T** on Monday, April 25, 2011 at 8:35am.

- physics ( help) -
**bobpursley**, Monday, April 25, 2011 at 9:21amHypothetically, do you ignore wind and air resistance?

Initial vertical velocity: 4.5sin30

go to the height equation:

hf=hi+InitialVelocityvertical*t-1/2 g t^2

hf=-30, hi=0 solve for time in air, t.

distance equation

horizonaldistance= 4.5cos30*timeinair

Hypothetically, with no air friction or force.

- physics ( help) -
**Jeff**, Wednesday, February 1, 2012 at 8:45pmFirst of all your initial vertical velocity is not 4.5 m/s.

it is Viy= 4.5 * sin(30)

and your horizontal = 4.5 * cos(30)

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