Math
posted by Meghan on .
A florist has access to 9 types of flowers and 8 types of foliage. He makes bouquets using 4 types of flowers and 3 types of foliage. How many different bouquets can he make?

For flowers, it's out of 9 choose 4, or C(9,4). For foliage, it's 8 choose 3, or C(8,3).
The formula for combinations, C(n,r) is n!/(r!(nr)!).
For flowers, C(9,4)=9!/(4!5!)=9*8*7*6/(1*2*3*4)=126.
Calculate similarly C(8,3) and multiply the two results together to get the number of different bouquets. 
Thanks!!!!!!!

You're welcome!