Thursday

August 21, 2014

August 21, 2014

Posted by **bode** on Saturday, March 26, 2011 at 11:40am.

a. The number of address lines needed for each memory chip

b. The number of data lines needed for each memory chip

c. The number of bytes that can be stored in each memory chip (note that there are 8 bits/byte)

128 KB words x 8 bits/word

512 KB words x 16 bits/word

512 MB words x 32 bits/word

8 GB words x 64 bits/word

- computer -
**MathMate**, Saturday, March 26, 2011 at 12:16pmAddress lines are required to address each word. For n lines, the number of possible address is 2^n addresses.

For 128K words, there are 2^7 addresses, so 7 address lines are required.

Each word has a width of 8 bits, so to address each bit individually (and internally), 8 lines are required.

The storage is

128K x 8bits

= 128K * 1 byte

= 128*2^10 bytes

= 131072 bytes

So answer for the first case is 7 address lines, 8 data lines and 131072 bytes.

The remaining cases are similar.

- computer -
**samrti**, Thursday, May 12, 2011 at 11:34amaddress lines is reqired in 512 k word memory

**Related Questions**

computer science - a) What is the largest positive number that can be ...

Algebra - Which of the following methods can be used to construct a pattern of ...

Algebra 2 - Which of the following methods can be used to construct a pattern of...

keybording and word processing - 1. When keying, it's important that you keep ...

math - the number of my hunderds plus the number of my thousandsin 3. the number...

computer sciece - The change in memory density with time can be described by B=...

math - the probability of a computer memory chip being defective is 0.02. which ...

URGENTlast question for Math - Which word phrase can be used to represent the ...

math,algebra - can someone correct this for me: Translate the following ...

math - Write a variable expression for each word phrase. 1. two times the number...