Posted by Trudy on Sunday, February 27, 2011 at 3:31pm.
37.43% by mass of WHAT?????. But you really don't need to do that.
Just use dimensional analysis and convert 55.5 g Cu(II) fluoride to fluorine.
55.5 g CuF2 x (2 moles F/1 mole CuF2) =??
Use atomic mass*2 for F and use molar mas for CuF2.
Copper (II) fluoride contains 37.42% F by mass. Use this percentage to calculate the mass of fluorine in grams contained in 24.0 g of copper (II) fluoride.
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