Posted by Cesar on Wednesday, February 23, 2011 at 8:35pm.
For x-> 0-,
f'(x) = d(-7x^2 + 7x)/dx = -14x+7 = 7
For x-> 0+,
f'(x) = d(3x^2 + 7x)/dx = 6x + 7 = 7
Since f'(0-) = f'(0+) = 7,
f'(0) exists, and equal to 7.
I already tried 7 for the first two... but the web ways that the answer is incorrect...
I have no idea why that's not the answer.....
You may want to check if there is no typo somewhere.
Other than that, I cannot think of anything else.
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