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December 21, 2014

December 21, 2014

Posted by **Anonymous** on Wednesday, January 19, 2011 at 7:53pm.

Does this system of linear equation have a solution of (-3,4)?

2x-3 = 6

y = 3x-13

Do u just substitute the numbers or something?

- MATH ALGEBRA -
**Reiny**, Wednesday, January 19, 2011 at 8:04pmYes, just substitute in both equations

1st:

Left Side = 2x-3 = 2(-3) - 3 = -9

but RS = 6, so the values don't even work in the first equation, you can stop here

(-3,4) is NOT a solution

I have a feeling that your first equation should have been

2x - 3y = 6

in that case:

LS - 2(-3) - 3(4) = -6

RS = +6

No point even trying the second

So no good either.

- MATH ALGEBRA -
**Anonymous**, Wednesday, January 19, 2011 at 8:06pmYes, sorry Reiny I had forgotton the Y. And thanks for the explanation:)

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