Posted by Anonymous on Wednesday, January 19, 2011 at 7:53pm.
How would u figure this question out?
Does this system of linear equation have a solution of (-3,4)?
2x-3 = 6
y = 3x-13
Do u just substitute the numbers or something?
- MATH ALGEBRA - Reiny, Wednesday, January 19, 2011 at 8:04pm
Yes, just substitute in both equations
Left Side = 2x-3 = 2(-3) - 3 = -9
but RS = 6, so the values don't even work in the first equation, you can stop here
(-3,4) is NOT a solution
I have a feeling that your first equation should have been
2x - 3y = 6
in that case:
LS - 2(-3) - 3(4) = -6
RS = +6
No point even trying the second
So no good either.
- MATH ALGEBRA - Anonymous, Wednesday, January 19, 2011 at 8:06pm
Yes, sorry Reiny I had forgotton the Y. And thanks for the explanation:)
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