Posted by **Josh** on Tuesday, January 11, 2011 at 2:32pm.

The equations y=-2X+12, y=6-X, and X=0 enclose a region in quadrant I. when that region is reflected over the line y=6-X, a portion of the reflection is in quadrant II. Find the area of that resulting region.

## Answer this Question

## Related Questions

- calculus - A region is bounded in the second quadrant by the curve y = ln(1–x), ...
- calculus - Which has more area, the region in the first quadrant enclosed by the...
- Calculus - Let R be the region in the first quadrant under the graph of y=1/sqrt...
- math - For the system of linear equations below, use graphing to determine in ...
- calculus - Find the volume of the solid generated by revolving the region about ...
- calculus - 1. Let R be the region in the first quadrant enclosed by the graphs ...
- Calculus (Area Between Curves) - Find the area of the region IN THE FIRST ...
- MATH - Region A that on xy-plane is bounded by two (2) curves and a line. The ...
- calculus - Sketch the region in the first quadrant enclosed by y=6/x, y=2x, and ...
- Calculus - Let f be the function given by f(x)=(x^3)/4 - (x^2)/3 - x/2 + 3cosx. ...

More Related Questions