algebra
posted by Michelle on .
I'm doing functions, and I don't know how I'm solving this equation wrong?
the equation is y = (x2)^2  1
when I graph it, the shape is supposed to be a parabola.
I'm using 2,1,0,1, and 2 as my X values.
But I'm getting 15, 8, 3, 0, and 1 for my Y values, respectively.

I'm not sure what you mean by solving it wrong, as you...don't appear to be solving it at all? Are you supposed to be finding the xintercepts?
The graph of this function is a parabola, with vertex at (h, k). You can find this vertex from the form y = a(xh)^2 + k. So, in this instance, the vertex is at (2, 1)  so that point will be the lowest point on the parabola.
The numbers you have chosen are all to the left of or equal to the x value of the vertex of the parabola, which is why they all decrease and never increase. If you use 3 or a larger number as an x value, you'll see that the numbers begin increasing  at x = 3, we would have y = (32)^2  1 = 0 again, and so on.
Does that answer your question, hopefully?