Posted by Michelle on Monday, December 6, 2010 at 6:36pm.
I'm doing functions, and I don't know how I'm solving this equation wrong?
the equation is y = (x2)^2  1
when I graph it, the shape is supposed to be a parabola.
I'm using 2,1,0,1, and 2 as my X values.
But I'm getting 15, 8, 3, 0, and 1 for my Y values, respectively.

algebra  Jennifer, Monday, December 6, 2010 at 7:45pm
I'm not sure what you mean by solving it wrong, as you...don't appear to be solving it at all? Are you supposed to be finding the xintercepts?
The graph of this function is a parabola, with vertex at (h, k). You can find this vertex from the form y = a(xh)^2 + k. So, in this instance, the vertex is at (2, 1)  so that point will be the lowest point on the parabola.
The numbers you have chosen are all to the left of or equal to the x value of the vertex of the parabola, which is why they all decrease and never increase. If you use 3 or a larger number as an x value, you'll see that the numbers begin increasing  at x = 3, we would have y = (32)^2  1 = 0 again, and so on.
Does that answer your question, hopefully?
Answer This Question
Related Questions
 pre cal  What is the center of the conic whose equation is x^2 + 2y^2  6x + 8y...
 algebra II  Can you please help me with the these problems. 8.Write an equation...
 math  How would I find the right window to graph a parabola in? The equation ...
 algebra 2  A quadratic equation can be written in vertex form or in standard ...
 Quadratic Equations and Functions  I started having trouble on part (c), and I ...
 Parabola Help  by plotting the graph of parabola y=2+3x2x^2 which 3 option are...
 Algebra  I am supposed to write the standard equation of the parabola with the ...
 Algebra  How can you tell an equation's real or imaginary roots just from its ...
 Quadratic Equations and Functions  I started having trouble on part (c), and I ...
 Trig  A parabola has its vertex on the graph of the line y=3x+1 and passes ...
More Related Questions