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March 26, 2017

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ab-bc+ad-dc/ab+bc+ad+dc

Simplify and state the domain

  • Trig/algebra2 - ,

    you probably meant ...

    (ab-bc+ad-dc)/(ab+bc+ad+dc)
    = (b(a-c) - d(a-c))/(b(a+c) + d(a+c))
    = (a-c)(b-d)/((a+c)(b+d))

    a ≠ -c , b≠ - d

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