THe total ticket sales for the basketball game were $1,625.00. Adult tickets were $7.00, and student tickets were $3.00. Twice as many students bought tickets as adults. How many student and adult tickets were sold?

S = 2A

7A + 3S = 1625

Substitute 2A for S in second equation and solve for S. Insert that value into the first equation and solve for A. Check by inserting both values into the second equation.

To find the number of student and adult tickets sold, we can set up a system of equations.

Let's assume the number of adult tickets sold is 'a' and the number of student tickets sold is 's'.

From the given information, we can set up two equations:

Equation 1: The total ticket sales were $1,625.00.
The cost of each adult ticket is $7, and the cost of each student ticket is $3.
So, the equation can be written as:
7a + 3s = 1625

Equation 2: Twice as many students bought tickets as adults.
This implies that the number of student tickets sold is double the number of adult tickets sold, or s = 2a.

We can substitute the value of 's' from Equation 2 into Equation 1 to solve for 'a'.

Substituting s = 2a into Equation 1, we get:
7a + 3(2a) = 1625
7a + 6a = 1625
13a = 1625
a = 125

Now that we have the value of 'a', we can substitute it back into Equation 2 to find 's':
s = 2a
s = 2(125)
s = 250

Therefore, 125 adult tickets and 250 student tickets were sold.