Post a New Question

posted by lomas on Thursday, October 28, 2010 at 1:30pm.

multiply: (2x^4y^2)^3 (4x^2y)^2 Is this right? 128x^11y^8 Not sure.

Did some rethinking..is it 128x^16y^8 ?

I got 128x^16y^8

Great...i was adding the exponents that were on the outside instead of multiplying it. Took me a while to remember the rule. Thanks Ron.

More Related Questions