Using a Standard deck of 52 cards, what is the probability of drawing four aces in a 5-card hand?
You want the case of
AAAAD , where A is aces and D is different from aces
or any permutation of that .
prob(AAAAD) = (4/52)(3/51)(2/50)(1/49)(48/48)
= 1/270725
but there are 5 arrangement of that AAAAD
so prob(your event) = 5/270725 or .0000185