Posted by mary on Saturday, October 16, 2010 at 2:31pm.
Follow TutorCat's site to find
z=(x-xmean)/standard deviation
to get
z=(600-500)/100=1
http://mathworld.wolfram.com/z-Score.html
The next step is to look up a probability table, or use your calculator to find out the one-tail probability (i.e. every score lower than 600). For a probability table, try:
http://www.math.unb.ca/~knight/utility/NormTble.htm
to find that for z=1.0, the probability is 84.13%.
Notice that for z=0 (exactly in the middle of the normal curve, or the mean =500, the probability is 0.5.
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