posted by Anonymous on .
Consider the following reaction: CH4 +2O2 -> CO2 + 2H2O. Delta H = -891 kJ
Calculate the enthalpy change for each of the following cases:
a. 1.00 g methane is burned in excess oxygen
b. 1.00 x 10^3 L methane gas at 740. torr and 25 *C is burned in excess oxygen
-891 kJ x 1/16 = ??
Use PV = nRT and solve for n, convert to grams, and use the same system as in a; i.e.,
-891 kJ x (grams/16) = ??