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January 29, 2015

January 29, 2015

Posted by **Koby** on Monday, September 20, 2010 at 12:38pm.

Not for sure if im doing this right.

For a) I used: change in x=vi*t; t=20m/20m/s

a) 1sec?

b) change in y=vi(of y) *t-1/2(g)(t^2)

20m=0*t-1/2(9.8)(t^2)

20m=4.9t^2

t^2=4.08

t=2.02 seconds

c) got 1.05 seconds, but that doesnt seem right to me, considering my answer for a)

Any help would be appreciated, especially if you can tell me where I'm going wrong.

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