Posted by Anonymous on Monday, September 20, 2010 at 11:13am.
2 identical cars capable of accelerating at 3.00m/s^2 are racing on a straight track with running starts. car A has an initial speed of 2.50m/s and car B has an initial speed of 5.00m/s. what is the seperation of the 2 cars after 10seconds? which car is moving faster after 10seconds.
do you use the equation x= v(initial)t + 1/2at^2 or v^2= v(initial)^2 + 2ax

physics  bobpursley, Monday, September 20, 2010 at 11:19am
I would combine both cars, to get separation directly:
separation=t*(v1v2)+1/2t^2 (A1A2)
Notice A1A2 is zero, so
separation=t(V1V2)
to find which car is faster, calculate the speed of each:
Vf=Vi+a*time