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physics

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2 identical cars capable of accelerating at 3.00m/s^2 are racing on a straight track with running starts. car A has an initial speed of 2.50m/s and car B has an initial speed of 5.00m/s. what is the seperation of the 2 cars after 10seconds? which car is moving faster after 10seconds.

do you use the equation x= v(initial)t + 1/2at^2 or v^2= v(initial)^2 + 2ax

  • physics - ,

    I would combine both cars, to get separation directly:

    separation=t*(v1-v2)+1/2t^2 (A1-A2)
    Notice A1-A2 is zero, so
    separation=t(V1-V2)

    to find which car is faster, calculate the speed of each:
    Vf=Vi+a*time

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