Posted by **John** on Monday, September 6, 2010 at 11:40pm.

sorry to repost (again) but I'm not understanding how to solve this:

A rocket is launched at an angle of 42◦ above the horizontal with an initial speed of 76 m/s. It moves for 9 s along its initial line of motion with an acceleration of 29 m/s^2. At this time

its engines fail and the rocket proceeds to move as a projectile.

The acceleration of gravity is 9.8 m/s^2.

a.) Find the maximum altitude reached by the rocket.

b.) What is its total time of flight?

c.) What is its horizontal range?

I know how to find these with constant acceleration (I think) but with the increasing acceleration I'm not sure.

Answers are:

a.) 3837.91 m

b.) 59.9965 s

c.) 14152.7 m

A tutor told me earlier I have to break this down into 2 parts: with increasing acceleration (engines on) and after (engines off) but I'm not sure how to do the first (engines on) part.

Thank you

Need to know how to solve, thank you.

## Answer This Question

## Related Questions

- Physics - sorry to repost (again) but I'm not understanding how to solve this: A...
- COLLEGE PHYSICS - A rocket is launched at an angle of 60.0° above the horizontal...
- Physics - sorry to keep posting this, but I have an assignment based on these ...
- Physics - A rocket is launched at an angle of 42◦ above the horizontal ...
- Physics - A rocket is launched at an angle of è = 48° above the horizontal with ...
- physics - A rocket is launched at an angle of 56.0° above the horizontal with an...
- physics - A rocket is launched at an angle of 56.0° above the horizontal with an...
- Physics - A rocket is launched at an angle of 50.0° above the horizontal with an...
- physics - A rocket is launched at an angle of 59.0° above the horizontal with an...
- Physics - A rocket is launched at an angle of 56.0° above the horizontal with an...

More Related Questions