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September 16, 2014

September 16, 2014

Posted by **cindy** on Monday, July 19, 2010 at 10:41am.

A. If 1 M&M plain cand is randomly selected, how likely is it that it weighs more than 0.8535 gram?

B. If 465 M&M plain candies are randomly selected, how likely is it that their mean weight is at least 0.8535 gram?

- statistics -
**PsyDAG**, Monday, July 19, 2010 at 1:20pmA. Z = (score-mean)/SD (for distribution of scores)

B. Z = (mean1 - mean2)/standard error (SE) of difference between means (for distribution of means)

SEdiff = √(SEmean1^2 + SEmean2^2)

SEm = SD/√(n-1)

Since only one SD is provided, you can use just that to determine SEdiff.

Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportions related to these Z scores.

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