Posted by Anonymous on Saturday, May 1, 2010 at 7:44pm.
The complete decay of Americium241 involves successively with a (alpha), a, B(beta), a, a, B, a, a, a, B, a production. Identify the 11 intermediate nuclides.
I did the first one,
^241_95 Am> ^4_2He + ^237_93Np
(hopes that doesn't look too confusing, ^ for root and _ for sub)
I'm having trouble doing the ones after the first decay.
2. ^237_93Np> ^4_2He + ^231_91Pa
it just doesn't add up to equal each other. What do I do?

Chemistry  DrBob222, Saturday, May 1, 2010 at 7:54pm
I did the first one,
^241_95 Am> ^4_2He + ^237_93Np
(hopes that doesn't look too confusing, ^ for root and _ for sub)
I'm having trouble doing the ones after the first decay.
2. ^237_93Np> ^4_2He + ^231_91Pa
2374 = 233 and 932=91 so ^233_91Pa and that adds up.
it just doesn't add up to equal each other. What do I do?

Chemistry  Anonymous, Saturday, May 1, 2010 at 8:48pm
Thanks DrBob!!
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