Posted by **Anonymous** on Saturday, May 1, 2010 at 7:44pm.

The complete decay of Americium-241 involves successively with a (alpha), a, B(beta), a, a, B, a, a, a, B, a production. Identify the 11 intermediate nuclides.

I did the first one,

^241_95 Am--> ^4_2He + ^237_93Np

(hopes that doesn't look too confusing, ^ for root and _ for sub)

I'm having trouble doing the ones after the first decay.

2. ^237_93Np--> ^4_2He + ^231_91Pa

it just doesn't add up to equal each other. What do I do?

- Chemistry -
**DrBob222**, Saturday, May 1, 2010 at 7:54pm
I did the first one,

^241_95 Am--> ^4_2He + ^237_93Np

(hopes that doesn't look too confusing, ^ for root and _ for sub)

I'm having trouble doing the ones after the first decay.

2. ^237_93Np--> ^4_2He + ^231_91Pa

**237-4 = 233 and 93-2=91 so ^233_91Pa and that adds up. **

it just doesn't add up to equal each other. What do I do?

- Chemistry -
**Anonymous**, Saturday, May 1, 2010 at 8:48pm
Thanks DrBob!!

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