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January 19, 2017
Posted by **Sarita** on Saturday, April 3, 2010 at 3:16pm.

B) So once that is found, then how can you prove that if 0(<or=)u(<or=)v(<or=)10, then 0(<or=)sqrt(u+1)(<or=)sqrt(v+1)(<or=)10?

- calculus -
**Damon**, Saturday, April 3, 2010 at 3:35pmHow do you prove that if 0(<or=)x(<or=)10, then 0(<or=)sqrt(x+1)(<or=)10?

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does the square root increase (is the derivative positive) as x goes from 0 to 10 ?

If so the left side of the domain is minimum and the right side is maximum of the function and we only need to test the ends.

d (x+1)^.5 / dx = .5 /sqrt(x+1)

that is positive everywhere in the domain so all we have to prove is the end points.

0 </= x </= 10

if x = 0

sqrt x+1 = sqrt 1 = 1

if x = 10

sqrt x+1 = sqrt 11 = 3.32

so

1 </ sqrt(x+1) </= 3.32 - calculus -
**Damon**, Saturday, April 3, 2010 at 3:37pmfor part b again the derivative is positive throughout the domain so if v is right of u then sqrt (1+v) > sqrt(1+u)

- calculus -
**Sarita**, Saturday, April 3, 2010 at 5:52pmthank you!

Additionally,

C) They give a recursively defined sequence: a_1=0.3; a_(n+1)=sqrt((a_n)+1)for n>1

How do you find out the first five terms for it. then prove that this sequence converges. What is a specific theorem that will guarantee convergence, along with the algebraic results of parts A and B? - calculus -
**Damon**, Saturday, April 3, 2010 at 7:26pm.3

sqrt 1.3 = 1.14

sqrt 2.14 = 1.46

sqrt 2.46 = 1.57

sqrt 2.57 = 1.60

hmmm, not getting bigger very fast.

let's see what happens to the derivative for large n

.5/sqrt(x+1)

ah ha, look at that. When n gets big, the derivative goes to zero. So the function stops changing. - calculus -
**Sarita**, Sunday, April 4, 2010 at 1:05pmBut why would you look for the derivative to go to zero? Does it have to do anything with the theorem: If summation of a_n converges then limit_(n-->infinity) of a_n = 0. If so, what would the limit be approaching? 10 or infinity? But if not, then what theorem would we use? I know you explained about the larger n for the derivative, but I do not understand how that relates to one of the theorems.

- calculus -
**Sarita**, Sunday, April 4, 2010 at 1:21pmBut doesn't it converge to infinity and not 0?

- calculus -
**Sarita**, Sunday, April 4, 2010 at 1:22pmwe want it to converge to 0 right? But does it even converge if it goes to infinity, or is that divergence?

- calculus -
**Sarita**, Sunday, April 4, 2010 at 2:28pmDo you do the limit on the derivative?

Or is there another way to prove convergence with a theorem of some sort?