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Would a drop of 40 Celsius degrees be more or less than a drop of 40 fahrenheit degrees? explain why

C = 5/9 (F - 32)40-32=8c
F = 9/5 C + 32 40+32=86f

  • math - ,

    look at the formula
    F = (9/5) C + 32
    each degree in C is roughly 2 units on the F scale
    so a change of 40 C would be (9/5)(40) or 72 F


    pick 2 readings which are appr. the same

    20C is roughly equal to 70 F
    drop each by 40 units
    compare -20C with 30 F

    -20C is rather nasty cold even for us Canadians, while 30F is almost balmy.

    What is your conclusion?

  • math - ,

    It would be more of a drop. But i still done get the formula. did i do the formula right in the first place?

  • math - ,

    There is only one formula, one is merely the rearrangement of the other.

    I don't know what you were trying to do.
    A line like
    C = 5/9 (F - 32)40-32=8c
    makes no sense

    What you are probably trying to do is find what
    40 F is in C, and then what
    0 F is in C

    ok, if F=40, C = (5/9)(40-32) = 4.44 C
    if F = 0, C = (5/9)(0-32) = - 17.78 C

    So a change of 40 in F resulted in a change of (4.44-(-17.78)) or 22.22 C roughly 1/2 as noted above in my first reply

  • math - ,

    Ok now that makes more sense to me. i must have typed it wrong. thank you.

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