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September 1, 2014

September 1, 2014

Posted by **Dylan** on Sunday, March 28, 2010 at 10:30pm.

C = 5/9 (F - 32)40-32=8c

F = 9/5 C + 32 40+32=86f

- math -
**Reiny**, Sunday, March 28, 2010 at 10:45pmlook at the formula

F = (9/5) C + 32

each degree in C is roughly 2 units on the F scale

so a change of 40 C would be (9/5)(40) or 72 F

or

pick 2 readings which are appr. the same

20C is roughly equal to 70 F

drop each by 40 units

compare -20C with 30 F

-20C is rather nasty cold even for us Canadians, while 30F is almost balmy.

What is your conclusion?

- math -
**Dylan**, Sunday, March 28, 2010 at 10:52pmIt would be more of a drop. But i still done get the formula. did i do the formula right in the first place?

- math -
**Reiny**, Sunday, March 28, 2010 at 11:05pmThere is only one formula, one is merely the rearrangement of the other.

I don't know what you were trying to do.

A line like

C = 5/9 (F - 32)40-32=8c

makes no sense

What you are probably trying to do is find what

40 F is in C, and then what

0 F is in C

ok, if F=40, C = (5/9)(40-32) = 4.44 C

if F = 0, C = (5/9)(0-32) = - 17.78 C

So a change of 40 in F resulted in a change of (4.44-(-17.78)) or 22.22 C roughly 1/2 as noted above in my first reply

- math -
**Dylan**, Sunday, March 28, 2010 at 11:16pmOk now that makes more sense to me. i must have typed it wrong. thank you.

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