Posted by **John** on Monday, March 1, 2010 at 3:27am.

Balance the following equations.

3. C12H22O11 + O2 = CO2 + H2O

Answer: C12H22O11 + 12 O2 = 12 CO2 + 11 H2O

8. CH3OH + O2 = CO2 + H2O

Answer: 2 CH3OH + 3 O2 = 2 CO2 + 4 H2O

I balanced all the others just fine. But I seem to be having trouble with these two. Can someone show me the steps to get to the answer?

Thank you very much.

- Chemistry (URGENT) -
**bobpursley**, Monday, March 1, 2010 at 6:35am
always start with the most difficult formula

C12H22O11 + O2>>CO2 + H20

ok, start then with the 12c

C12H22O11 + O2>>12CO2

Next, H 22

C12H22O11 + O2>>12CO2 + 11H2O

now you have to go back and forth on the O. Since the products are balanced, add the O in th products. 12*2+11=35

In the sucrose formula, you have 11, so that means you need 24O

C12H22O11 + 12O2>>12CO2 + 11H2O

done.

next, start with the CH3OH, the C

CH3OH +O2>>CO2

balanced, then the H

CH3OH + O2>>CO2+ 2H2O

Now, the O THe right side is OK on C and H. Lets start there. On the right side 4, so we need 4 on the left.

CH3OH + 3/2 O2>>CO2 + 2H2O

and it is balanced. Well, some folks in the US get all unbalanced about fraction coefficents (coefficents represent mole ratios, so it is ok. But some folks think like John Dalton did, that the coefficents represent individual molecules, and fractions are not nice). So to placate those individuals, if we get rid of the 3/2..multipy all by 2

2CH3OH + 3O2>>2CO2+4H2O

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