posted by Dawn .
Perform the indicated operations and write the answer in the form a + bi, where a and b are real numbers.
Problem #1 (3+2i)^2
Problem #2 i^3 - i^2
Notice the following pattern of powers of i
i = √-1
i^2 = √-1√-1 = -1
i^3 =i(i^2) = i(-1) = -i
i^4 = (i^2)(i^2) = (-1)(-1) = +1
i^5 = i(i^4) = i(1) = i
Can you see the pattern
for your first question , just expand it like you would (a+b)^2, then replace the powers of i
for the second, you should be able to do it following the above patterns
thanks...can I ask u to tell me if I'm correct when I do the problems please and repost back?
are these the correct answers??
problem #1: (3+2i)^2=
problem #2: i^3-i^2=
No, not right
(3+2i)^2= 9+12i+4i^2= 9+12i-4=5+12i
is this the answer bob purley??? thanks for your help!!
You need to check it and answer for yourself it is it right.
it makes sense now...thanks!!
i^3 - i^2=
-i + the square root of -1^2=
-i + 1i
is this correct?