Posted by Dawn on Tuesday, February 9, 2010 at 9:56am.
Perform the indicated operations and write the answer in the form a + bi, where a and b are real numbers.
Problem #1 (3+2i)^2
Problem #2 i^3  i^2

math  Reiny, Tuesday, February 9, 2010 at 10:45am
Notice the following pattern of powers of i
i = √1
i^2 = √1√1 = 1
i^3 =i(i^2) = i(1) = i
i^4 = (i^2)(i^2) = (1)(1) = +1
i^5 = i(i^4) = i(1) = i
Can you see the pattern
for your first question , just expand it like you would (a+b)^2, then replace the powers of i
for the second, you should be able to do it following the above patterns 
math  Dawn, Tuesday, February 9, 2010 at 11:17am
thanks...can I ask u to tell me if I'm correct when I do the problems please and repost back?

math  Dawn, Tuesday, February 9, 2010 at 11:32am
Reiny...
are these the correct answers??
problem #1: (3+2i)^2=
(a+b)^2=
(3+2times1)=
(3+1)^2=
4^2= 16
problem #2: i^3i^2=
ab=
i 1
?????????????????????????? 
math  bobpursley, Tuesday, February 9, 2010 at 11:48am
No, not right
(3+2i)^2= 9+12i+4i^2= 9+12i4=5+12i
check that. 
math  Dawn, Tuesday, February 9, 2010 at 12:08pm
is this the answer bob purley??? thanks for your help!!

math  bobpursley, Tuesday, February 9, 2010 at 12:44pm
You need to check it and answer for yourself it is it right.

math  Dawn, Tuesday, February 9, 2010 at 1:10pm
it makes sense now...thanks!!

math  Dawn, Tuesday, February 9, 2010 at 2:25pm
PROBLEM 2....
i^3  i^2=
i + the square root of 1^2=
i + 1i
is this correct?